Math, asked by luciexforstudy9842, 5 hours ago

The 12th term of a G.P. whose first term is 1/8 and second term is 1/2 is

Answers

Answered by shankardagamgmailcom
0

Answer:

the first term divide by second term 1/2-1/8=4-1/8=3/8

Answered by pulakmath007
18

SOLUTION

TO DETERMINE

The 12th term of a G.P. whose first term is 1/8 and second term is 1/2

EVALUATION

Here it is given that for the given GP

First term = a = 1/8

Second Term = 1/2

Common Ratio = r

= Second Term ÷ First term

= 4

So 12 th term of the GP

 \displaystyle \sf{ = a \times  {r}^{n - 1} }

 \displaystyle \sf{ =  \frac{1}{8}  \times  {4}^{12 - 1} }

 \displaystyle \sf{ =  \frac{1}{8}  \times  {4}^{11} }

 \displaystyle \sf{ =  \frac{1}{8}  \times  {4}^{11} }

  \sf{= 524288}

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