the 12th term of an Ap is-13 and the sum of its first four terms is 24 . find the sum of its 10th term . please give me solution step by step by (actually mai abhi ye question kar rahi hoo or mujhe bich mai thodi confusion hai so please send the right answer now)
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the 12 term is -13 so a+11d=-13...(1)
and sum of first four term is 24 so,
2(2a+3d)=24
2a+3d=12...(2)
from equating 1 and 2
-19d=38
d=-2
and if we substitute value in eq 1 then
a=9
sum of first 10 term is n/2(2a+(n-1)d)
10/2+(2×9+9×-2)
=0
sum of 10 term is 0
hope it helps......
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