Question

The 12th term of an AP is -13 and the sum of its first four terms is 24,find the sum of its first 10 terms.​

Answer 1

Answer:

Step-by-step explanation:

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→$GIVEN\\ t_{12}=a+(n-1)d=-13$

→   $s_{n}=\frac{n}{2}(2a+(n-1)d)=24$

→   $a+11d=-13$

→   $4a+3d=24$

→   $3a-8d=37$