The 12th term of an AP is double the 5th term. Find the common difference, give thhat the first term is 7.
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a= 7 (given),
T12 = 2 × T5,
a+(12-1)d = 2 × [a+(5-1)d],
a+11d=2a+8d,
then
11d-8d=2a-a,
3d=a,
3d=7,
then
d=7/3
T12 = 2 × T5,
a+(12-1)d = 2 × [a+(5-1)d],
a+11d=2a+8d,
then
11d-8d=2a-a,
3d=a,
3d=7,
then
d=7/3
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hope it helps you mate
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