Question

The 12th term of an arithmetic progression has the value 0. Which term of the AP is 3 times the
17th element?​

Answer 1

Answer:

don't know sorry bro really sorry

Answer 2

Answer:

27th term.

Step-by-step explanation:

12th term = a + 11d = 0

so, 13th term = a + 12d = a + 11d + d = d

14th term = 2d so on

27th term = 15d. ....... (a)

Now, let nth term = 3(17th term)

implies, nth term = 3(a + 16d) = 3(a + 11d + 5d)

but a + 11d = 0.(given)

So, nth term = 15d, which is 27th term.

hence 27th term is 3 times 17th term