Math, asked by reecelarissah, 1 day ago

the 12th term of an arithmetic sequence is 29. if the 3rd term is subtracted from the 7th term the result is -8. what is the 52nd term?​

Answers

Answered by ImperialGladiator
39

Answer:

52th term of the A.P. is 109

Explanation:

We know that,

nth term of an A.P. :-

 \rm \implies \: a_n = a + (n - 1)d

Where,

  • a denotes the first term.
  • n is the number of terms.
  • d represents the common difference.

Now,

12th term of the A.P. series is 29. (given)

\rm \therefore \: a_{12} = 29

\rm \implies \: a + (12 - 1)d = 29

\rm \implies \: a + 11d = 29

\rm \implies \: a = 29 - 11d

Now,

it is given that, the difference between \rm a_3 and \rm a_7 is -8.

\rm \therefore \: a_{3} - a_{7} = -8

{ \rm \implies  \{a + (3 - 1)d \} - \{a + (7 - 1)d \} = -8}

 \rm \implies  \{a + 2d \} - \{a + 6d \} = -8

Substitute a :-

{ \rm \implies  \{29 - 11d + 2d \} - \{29 - 11d + 6d \} =  - 8}

Soliving further,

{ \rm \implies  \{29 - 9d \} - \{29 - 5d \} =  - 8}

{ \rm \implies  29 - 9d - 29  + 5d =  - 8}

{ \rm \implies   - 4d =  - 8}

{ \rm \therefore   d = 2}

Calculate the value of a :-

 \rm \implies \: a = 29 - 11d

we have,

  • d = 2

 \rm \implies \: a = 29 - 11(2)

 \rm \implies \: a = 29 - 22

 \rm \implies \: a = 7

Now, 52th term of the A.P. is given by,

\rm \implies \: a_{52} = 7 + (52 - 1)2

\rm \implies \: a_{52} = 7 + (51)2

\rm \implies \: a_{52} = 7 + 102

\rm \therefore \: a_{52} = 109

Required answer: 109

Answered by vvsns0588
19

Answer:

the 12th term is −46

Step-by-step explanation:

A term of an arithmetic sequence can be calculated with the formula:

tn=a+(n−1)d

where:tn=any term in the arithmetic sequence a=  first term n=term number/number of terms, d= common difference

To find the 12th term of the sequence, we first need to find d, the common difference. We can do this by subtracting t1 from t2: t2−t1=14−20=−6

Now that you have the common difference, substitute all your known values into the formula to solve for

t12:

tn=a+(n−1)dt12=20+(12−1)(−6)t12=

20+(11)(−6)t12=

20−66t12=

−46

∴, the 12th term is −46.

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