The 13 term of an AP in two times ita 10 term and the third term is 6 more than two
Inth term Hind the sum of first three terms of the All
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Please write question properly!! i can't understand it..."than two
Inth term Hind" ....what's this???
a₁₃=2×a₁₀
a₃=6+a₂
a+2d=a+d+6
=>d=6
a+12d=2a+18d
or a+6d=0
a+(6)6=0
=>a=–36
so, S₃=n/2(2a+(n-1)d
=3/2(2(–36)+(2)(6)
=3/2(–72+12)
=3/2(–60)
=3×–30
S₃= –90
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refer to the attachment
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