The 13 term of an AP is thrice its 3rd term. If its 6* term is 8, then find the sum of its first 30 terms.
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Step-by-step explanation:
1) a13=3a3
a+(n-1) d=3(a+(n-1) d)
a+nd-d=3a+3nd-3d
2a-2nd-2d=0
a-nd-d=0...... (1)
a6=8
a+(n-1) d=8
a+nd-d=8....(2)
solve 1.2
and get a and d
after
s30=n/2(2a+(n-1) d)
put value here
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