the 13th term of a. p is 3 and the sum of first 13 terms is 234. find the common differendifference and the sum of first 21 terms
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Step-by-step explanation:
given 13th term is 3
so a+12d =3 [a is first term and d is difference]
and sum is 234
so n/2[2a+(n-1)d]=234
after equating we get a +6d = 36
so a+12d= 3
a+6d=36
after equating we get d= -33/6 and a= -63
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