Question

The 13th term of an A.P whose first term and common difference respectively are 3/2 and 2/3​

Answer 1

Answer:

$a = \frac{3}{2} \\ d = \frac{2}{3} \\ a13 = a + 12d \\ = \frac{3}{2} + 12 \times \frac{2}{3} \\ = \frac{3}{2} \: \: + 8 \\ = \frac{3 + 16}{2} \\ = \frac{19}{2}$

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