the 13th term of the series is is 1+5+9.......
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Answer:
A = 1 , d = 5 - 1 = 4 ,
T13 = a + (n-1)d
= 1 + (13-1)×4
= 1 + 12 × 4
= 1 + 48 = 49.
Hope it helps
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