The 14th term from the end of AP 2, 6, 10, 14..... 130 is
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Answer:
a=2
d=6-2=4
an=130
an=a+(n-1) d
130=2+(n-1) 4
130=2+4n-4
130=4n-2
130+2=4n
132=4n
n=132/4
n=33
14th term
a14=a+(n-1) d
a14=2+(14-1) 4
=2+13*4
=2+52
=54
Hence, 14 th term is 54.
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