The 14th term of an AP is twice its 9th term. If its 6th term is -8, then find the sum of its first 20 terms
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Answered by
14
Answer:
-520
Step-by-step explanation:
a+5d=-8......(i)
=>a+13d=2(a+8d)
=>a+13d=2a+16d
=>a=-3d......(ii)
So,
-3d+5d=-8
=>2d=-8
=>d=-4
So,
a+5(-4)=-8
=>a-20=-8
=>a=12
20th term = a+19d=12+19(-4)=12-76=-64
So,
S20= n/2(a+l)
=20/2(12-64)
=10(-52)
=-520 (Ans)
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