the 15th term of AP is 3 more than twice the 7th term if 10th term of AP is 41
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THE QUESTION PROVIDED IS INCOMPLETE SO I GAVE SOLUTION OF Nth TERM NOW YOU CAN FIND ANY TERM NEEDED BY PUTTING THE VALUE OF N IN ANSWER
a+14d=2(a+6d)+3
⇒a-2d+3=0 ...(i)
again
a+9d=41 (ii)
subtracting i from ii
11d=44
⇒d=4
hence from ii
a=5
hence nth term = 5+ (n-1) x4
=4n+1
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