Question

the 15th term of arithemetric progression x-7,x-2,x+3....is

Answer 1

a+14d
d=x-2-x+7
d=5

now a+14d
x-7+14(5)
x+63

so the 15th term is x+63

Answer 2

$a_{15}$=a+14×d                                      a=x-7
   =x-7+14×5                                d=x-2-(x-7)
   =x-7+70                                    d=5
   =x+63