The 15th term of the AP-5/2,0
5/2,... is
(a) -30
(c) 30
(b) 20
(d) -20
Answers
Answered by
1
Answer:i think it is non of it
Step-by-step explanation:
we know that an=a1+(n-1)d
d=a2-a1
i.e 0-(-5/2)=5/2
⇒ a15= -5/2+(15-1)*5/2
= -5/2+14*5/2
here 14 cancles by 2
then, = -5/2+35
= (-5+70)/2
= 65/2
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