Question

the 16 term of an ap is more than twice its 8th term of the 12th term of the ap is 47 find its and the term​

Answer 1

Solution:-

Given : a₁₂ = 47  or a + 11d = 47

a₁₆ = a + 15d and a₈ = a +7d

Now, according to the question

2(a + 7d) + 1 = a + 15d

2a + 14d + 1 = a + 15d

2a - a = 15d - 14d - 1

a = d -1 .................(1)

Substituting the value of 'a' in a + 11d = 47, we get

d - 1 + 11d = 47

12d = 47 + 1

12d = 48

d = 4

Substituting the value of 'd' in a + 11d = 47, we get

a + 11*4 = 47

a = 47 - 44

a = 3

Now

nth term = a + (n - 1)d

= 3 + (n - 1)4

= 3 + 4n - 4

nth term = 4n - 1

hope it helps

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Answer 2

Answer:

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