the 16th term of an AP is 17 and 13th term is 38 find the 19th term
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Solution
let the first term is=a
last term is =l
and the difference is =d
now ...
a(16)=a+(16-1)d=17
=>a+15d=17......(1)
and ...
a+12d=38.........(2)
from equation(1 )and (2)...
a+15d=17
a+12d=38
___________
3d=-21
=>d=-7
now ....a=17-15(-7)=17+105=122
therefore the 19th term is ...
a(17)=122+(19-1)(-7)=122-126=-4
Hope this helps you......xd
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