The 16th term of an ap is 5 times its 3rd term. If its 10th term is 41 then find the sum of its first 15 terms. use elimination meathod
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a+15d=5*(a+2d)
a+15d=5a+10d
5d=4a
a+9d=41
5d/4+9d=41
41d/4=41
d=4,a=5
sum=15/2(10+56)
sum=15*33
495
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