the 17^15 term of ap exceed it's 10^15 term by 7 the common difference
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Divide 5x3 − 15x2 + 25x by 5x.
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Qᴜᴇꜱᴛɪᴏɴ :
❥ the 17^15 term of ap exceed it's 10^15 term by 7 the common difference
ᴀɴꜱᴡᴇʀ :
➩ Given that the 17th term of an A.P. exceeds its 10th term by 7.
d = ?
➟ a + 16 d = 1 + 9 d + 7
➟ 16 d - 9 d = 7
➟ 7 d = 7
➟ d = 7 / 7
➟ = 1
Therefore , common difference = 1 .
Hope it helps uhh !! ♥
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