Math, asked by ahapshangham435, 4 months ago

the 17^15 term of ap exceed it's 10^15 term by 7 the common difference ​

Answers

Answered by IND21
1

Answer:

Divide 5x3 − 15x2 + 25x by 5x.

ANSWER:

Answered by MysticCharm
2

Qᴜᴇꜱᴛɪᴏɴ :

the 17^15 term of ap exceed it's 10^15 term by 7 the common difference

ᴀɴꜱᴡᴇʀ :

Given that the 17th term of an A.P. exceeds its 10th term by 7.

d = ?

a + 16 d = 1 + 9 d + 7

16 d - 9 d = 7

7 d = 7

d = 7 / 7

= 1

Therefore , common difference = 1 .

Hope it helps uhh !!

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