Question

the 17 th term of an A.P exceeds it's 10 th term by 7the common difference of the the A.P is
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Answer 1

Answer:

We know that,

an=a+(n-1)d

So,

17th term is a17=a+16d

and 10th term is a10=a+9d

Given

a17-a10=7

therefore,

a+16d-(a+9d)=7

a+16d-a-9d=7

16d-9d=7

7d=7

d=1

Therefore the common difference is 1.

Answer 2

Answer:

1 is the common difference

Step-by-step explanation:

let the 17th and 10th term of an AP be a17 and a10

according to the question

a17=a10+7

put the formula an = a+(n-1)×d

a + (17-1)d=a+(10-1)d+7

a+16d=a+9d+ 7

a-a+16d-9d=7

7d=7

d=7/7

d=1