the 17 th term of an A.P exceeds it's 10 th term by 7the common difference of the the A.P is
Answers
Answered by
1
Answer:
We know that,
an=a+(n-1)d
So,
17th term is a17=a+16d
and 10th term is a10=a+9d
Given
a17-a10=7
therefore,
a+16d-(a+9d)=7
a+16d-a-9d=7
16d-9d=7
7d=7
d=1
Therefore the common difference is 1.
Answered by
1
Answer:
1 is the common difference
Step-by-step explanation:
let the 17th and 10th term of an AP be a17 and a10
according to the question
a17=a10+7
put the formula an = a+(n-1)×d
a + (17-1)d=a+(10-1)d+7
a+16d=a+9d+ 7
a-a+16d-9d=7
7d=7
d=7/7
d=1
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