the 17 th term of an ap exceed its 10 th term by 7. find the common difference
Answers
Answered by
3
Answer:
a17-a10=7
=>(a+16d)-(a+9d)=7
=>a+16d-a-9d=7
=>7d=7
=>d=1
Answered by
6
Answer:
Given that the 17th term of an A.P exceeds its 10th term by 7 . d = ? ⇒d = 7/7 = 1 . Therefore , common difference = 1 .
abhi nai adi ᕙ(⇀‸↼‶)ᕗ
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