The 17 th term of an ap exceeds its 10th term by 7 . Find a and d
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a17=a+16d........... (1)
a10=a+9d...............(2)
a17=a10+7
a+16d=a+9d+7
a-a+16d-9d=7
7d=7
d=7/7
d=1
now put value of d in eq. 1
a +16d=0
a+16*1=0
a+16=0
a=-16
d=1 and a= -16
if it is hlp u then mark as brilliant
a10=a+9d...............(2)
a17=a10+7
a+16d=a+9d+7
a-a+16d-9d=7
7d=7
d=7/7
d=1
now put value of d in eq. 1
a +16d=0
a+16*1=0
a+16=0
a=-16
d=1 and a= -16
if it is hlp u then mark as brilliant
disharai:
How can u say that a+ 16d as 0
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