Question

the 17 the term of the AP exceeds its 10 the term by 7

Answer 1

Step-by-step explanation:

let first term and common difference of ap be a and d

now

17th term=10th term+7

a+(17-1)d = a+(10-1)d+7

16d=9d+7

16d-9d= 7

7d = 7

d=7/7=1

common difference =1

Answer 2

Step-by-step explanation:

refer to the attachment