The 17th team of an AP exceed its 10th term by 7. Find the D
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Sol: Let a be the first term and d be the common difference of A.P. 17th term of A.P t17 = a + 16d. 10th term of A.P is t10 = a + 9d. Given that 17th term of an A.P exceeds its 10th term by 7. a + 16d = a + 9d + 7 7d = 7 ∴ d = 1
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17th team = a +(17-1)d= a+16d----------1
10th term = a+(10-1)d=a+9d-------------2
A/Q
=> a+9d+7= a+16d
=>5d = 7
=>d=7/5
10th term = a+(10-1)d=a+9d-------------2
A/Q
=> a+9d+7= a+16d
=>5d = 7
=>d=7/5
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