The 17th term of an A.P. exceed its 10th term by 7 find its common difference
Answers
Answered by
3
Answer.
Let a be the ist term and d be the common difference.
a+16d = a+ 9d + 7
16d - 9d = 7
7d = 7
d= 7/7
d= 1
Therefore common difference =1
Similar questions