Math, asked by dhruthikanishin999, 8 months ago

The 17th term of an AP exceed its 10th term by 7.find the common difference

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Answered by Anonymous

Let a be the first term and d be the common difference of A.P.

17th term of A.P t17 = a + 16d.

10th term of A.P is t10 = a + 9d.

Given that 17th term of an A.P exceeds its 10th term by 7.

a + 16d = a + 9d + 7

7d = 7

∴ d = 1

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Answered by TheEternity

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