Question

the 17th term of an ap exceeds its 10th by 7. Find the common difference.​

Answer 1

Answer:

1

Step-by-step explanation:

a+16d - (a+9d) = 7                                                

a + 16d - a + -9d =7

7d =7

d= 1

Answer 2

Answer:

d=1

Step-by-step explanation:

Let a be the 1st term and d be the common difference of an ap

Given,

$T_{17}$ = a + 16d

$T_{10}$ = a + 9d

$T_{17} = T_{10} + 7$

a + 16d = a + 9d + 7

7d = 7

d = 1