Question

the 17th term of an AP exceeds its 10th term by 7. find cd?​

Answer 1

Answer: cd = 1

Step-by-step explanation:

a17 = a + 16d where d is the common difference and a is the first term

a10 = a + 9d

a17-a10 = 7

ie. a+16d - a- 9d = 7

or 7d = 7

Hence d = 1

Answer 2

Answer:

17th term is a+16d

10ty term is a+9d

then

a+9d+7=a+16d

7d=7

d=1

ok

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