Question

The 17th term of an AP exceeds its 10th term by 7. Find the common difference.​

Answer 1

Answer:

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Answer 2

Let a and d be the first term and common difference of the AP

Given that,

17th term = 10th term + 7

$\implies \: \sf{a + 16d = a + 9d + 7} \\ \\ \implies \: \sf{ \cancel{a} + 16d = \cancel{a} + 9d + 7} \\ \\ \implies \: \sf{7d = 7} \\ \\ \: \implies \: \boxed{\sf{d = 1}}$

Thus,the common difference of the AP is 1