Question

the 17th term of an ap exceeds its 10th term by 7 find the common difference .​

Answer 1

Step-by-step explanation:

1st term=a

common difference =d

Now, 17th term and 10th term by 7

a+(n-1)d=a+(n-1)d+7

a+(17-1)d=a+(10-1)d+7

a+16d=a+9d+7

a-a+16d-9d-7=0

7d-7=0

7d=7

d=7/7

d=1

Therefore, the required common difference is 1

Answer 2

Answer:

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