Question

the 17th term of an ap exceeds its 10th term by 7 find the comman difference?​

Answer 1

Answer:

it's a simple formula.

Answer 2

Answer :

common difference = 1

Explanation :

Given,

17th term = 7 + 10th term

$a_{17} = 7 + a_{10}$ -----equation 1

→ $a_n$ = a + (n - 1)d

→ $a_{17}$ = a + (17 - 1)d

→ $a_{17}$ = a + 16d ------ equation 2

Similarly,

$a_{10}$ = a + 9d ------ equation 3

Substitute equations 2 and 3 in 1.

→$a_{17} = 7 + a_{10}$

→ a + 16d = 7 + a + 9d

→ 16d - 9d = 7

→ 7d = 7

→ d = 1

Therefore,

$\boxed {d = 1}$