Question

the 17th term of an AP exceeds its 10th term by 7 find the common difference​

Answer 1

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Answer 2

Answer:

a=3

d=15-3=12

an=a54+132

a+(n-1)d=a+54d+132

(n-1)12=53 (12)+132

(n-1)12=636+132

(n-1)12=768

n-1=

$768 \div 12 = 64 \\ n - 1 = 64 \\ \\n = 64$

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