Question

The 17th term of an AP exceeds its 10th term by 7. Find the common difference.
OR
How many multiples of 4 lie between 10 and 250?
2​

Answer 1

it is given that common difference (d) = 4

a = 12 because it is first number which is divisible by 4 in 2 digit

An = 248 last term divisible by 4 in 250

An=a(n-1)×d

248 = 12(n-1)×4

248-12 = (n-1)×4

236 = (n-1)×4

236/4 = (n-1)

59 = n-1

59+1 = n

Answer 2

ur answer is attached...