Question

The 17th term of an AP exceeds its 10th term by 7. find the common difference .

Answer 1

Answer:

⇒a

n

=a+(n−1)d

⇒a

17

=a+16d....(1)

⇒a

10

=a+9d.....(2)

⇒a

17

−a

10

=7

⇒(a+16d)−(a+9d)=7

⇒7d=7

⇒

d=1

Step-by-step explanation:

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Answer 2

Answer:

Common difference is 1.

Step-by-step explanation:

17th term = a+(n-1)d = a+16d

10th term = a+(n-1)d = a+9d

So, (a+16d)-(a+9d) = 7

=> 7d = 7

=> d = 1

So, Common difference is 1.

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