the 17th term of an ap exceeds its 10th term by 7 find the common difference
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Answer:
Given,
a₁₇ = a₁₀ + 7
→ a + (17 - 1)d = a + (10 - 1)d + 7
→ 16d = 9d + 7
→ 7d = 7
→ d = 7 ÷ 7
→ d = 1
Therefore, the common difference is 1.
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