The 17th term of an AP exceeds its 10th term by 7. Find the common difference
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Answer:
a7-a10 = 7
a+(7-1)d - [a+(10-1)d] = 7
a+ 6d- a - 9d = 7
6d - 9d = 7
-3d = 7
d = 7/-3
d = -7/3
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