Question

the 17th term of an arithmetic progression exceeds its 10th term by 7.find the common difference.​

Answer 1

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☞ Common Difference = 1

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✭ 17 th term of an AP exceeds it's 10 th tem by 7

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◈ The Common Difference?

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≫ Assume that a as the first term and d as the common difference

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➝ $\sf a_{17} - a_{10} = 7a$

Calculating,

➳ $\sf\bigg\lgroup a + 16d\bigg\rgroup - \bigg\lgroup + 9d\bigg\rgroup = 7$

➳ $\sf 7d = 7$

➳ $\sf\orange{d = 1}$

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Answer 2

Answer:

here a17=a10+7

THEN,a+16d=a+9d+7

here a are canceled

16d=9d+7

16d-9d=7

7d=7

d=7/7

d=1

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