Question

The 17th term of an arithmetic sequence is 8 more than its third term. If the sum of first and 19th term is 46

Answer 1

Answer:

a17=a3+8

a1+16d=a1+2d+8

14d=8, d=4/7

a1+a19=46

a1+a1+18d=46

2a1+18×(4/7)=46

2a1=46-(72/7)

a1=(47×7-72)/7