Question

the 17th term of the AP: 6,9, 12,15..........is=?​

Answer 1

Answer:

let, t1 = 6 and d= 3

Formulae= tn= t1 +(n-1) d

put the value we get

t17=6+(17-1)3

=6+16*3

=6+48

=54

Answer: 54

hope help you.......

Answer 2

$\huge\mathbb{SOLUTION:-}$

Formula used :-

$\bigstar{\sf{\boxed{\sf{T_n=a+(n-1)d}}}}$

• Here :-

$\sf \bullet a=6\:\:\:\bullet d=9-6= 3\\ \sf \:\: \bullet\: n=17$

Now

$\sf\underline{\purple{\:\:\:A.T.Q\:\:\:}}$

$\sf:\implies T_n=a+(n-1)d\\ \\ \sf:\implies T_{17}=6+(17-1)\times 3\\ \\ \sf:\implies T_{17}= 6+16\times 3\\ \\ \sf:\implies T_{17}=6+48\\ \\ \sf:\implies T_{17}= 54$

So the 17th Term of Given AP is 54