Question

The 17th term of the AP exceeds 10th term by 7 . Find the common difference

Answer 1

This is the answer

Hope it helps☺️

Answer 2

Answer:

$(t17) - (t10) = 7$

$(a + 16d) - (a + 9d) = 7$

$= 7d = 7$

$= d = 1$

so common difference is 1

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