the
18. A bag contains 750 in the form of rupee, 50 P and 25 P coins in the ratio 5:8:4. Find the
number of coins of each type.
20. If 4x + 5): (3x +11) = 13:17. find the value of x.
Answers
Answered by
3
Answer:
Step-by-step explanation:
Total amount in the bag=Rs 750
Let the number of rupee be 5x, number of 50 paisa coin be 8x and number of 25 paisa coin be 4x
According to the question
5x(1)+8x(0.5)+4x(0.25)=50
5x+4x+x=750
10x=750
x=75
Therefore,
Number of coin of rupee=5×75=375
Number of coin of 50 paisa =8×75=600
Number of coin of 25 paisa=4×75=300
Answered by
2
Answer:
Total amount in the bag=Rs 750
Let the number of rupee be 5x, number of 50 paisa coin be 8x and number of 25 paisa coin be 4x
According to the question
5x(1)+8x(0.5)+4x(0.25)=50
5x+4x+x=750
10x=750
x=75
Therefore,
Number of coin of rupee=5×75=375
Number of coin of 50 paisa =8×75=600
Number of coin of 25 paisa=4×75=300
"but when the ratio is 5:8:4"
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