Question

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18. A bag contains 750 in the form of rupee, 50 P and 25 P coins in the ratio 5:8:4. Find the
number of coins of each type.
20. If 4x + 5): (3x +11) = 13:17. find the value of x.​

Answer 1

Answer:

Step-by-step explanation:

Total amount in the bag=Rs 750

Let the number of rupee be 5x, number of 50 paisa coin be 8x and number of 25 paisa coin be 4x  

According to the question

5x(1)+8x(0.5)+4x(0.25)=50

5x+4x+x=750

10x=750

x=75

Therefore,

Number of coin of rupee=5×75=375

Number of coin of 50 paisa =8×75=600

Number of coin of 25 paisa=4×75=300

Answer 2

Answer:

Total amount in the bag=Rs 750

Let the number of rupee be 5x, number of 50 paisa coin be 8x and number of 25 paisa coin be 4x

According to the question

5x(1)+8x(0.5)+4x(0.25)=50

5x+4x+x=750

10x=750

x=75

Therefore,

Number of coin of rupee=5×75=375

Number of coin of 50 paisa =8×75=600

Number of coin of 25 paisa=4×75=300

"but when the ratio is 5:8:4"