Question

the 18th term of an ap root2,3root2,5root2 is......................

Answer 1

Answer:

35√2

Step-by-step explanation:

nth term in AP = a + (n - 1)d,  a is first term and d is common difference.

Here,

a = first term = √2

com. dif. = 3√2 - √2 = 2√2

Therefore, 18th term:

⇒ √2 + (18 - 1)(2√2)

⇒ √2 + (17)(2√2)

⇒ √2 + 34√2

⇒ 35√2

Answer 2

$\huge \: answer : \\ \\ a = \sqrt{2} \\ \\ d = 3 \sqrt{2} - \sqrt{2} = 2 \sqrt{2} \\ \\ n = 18 \\ \\ formula \: \: used : \\ \\ a_n = a + (n - 1)d \\ \\ a_{18} = \sqrt{2} + (18 - 1)2 \sqrt{2} \\ \\ a_{18} = \sqrt{2} (17)2 \sqrt{2} \\ \\ a_{18} = \sqrt{2} + 34 \sqrt{2} \\ \\ a_{18} =35 \sqrt{2} \\ \\ 8 \: \: th \: \: term \: \: of \: \: ap \: \: is \: \: 35 \sqrt{2}$