Question

The 19th term of an AP is equal to 3 times it's 6th term . If it's 9th term is 19, then the AP​

Answer 1

Answer:

a is 57/19 and common difference is 19a/3 rest part u sole it

Answer 2

Answer:

AP : 3,5,7,9,11,......

Step-by-step explanation:

Given

a 9= 19 => a+8d = 19------------> eq 1

a 19 = 3( a 6)

=> a+18d = 3(a+5d)

=> a+18d = 3a+15d

=>2a= 3d

=> 2a-3d= 0 ------------> eq 2

Multiply eq 1 by 2

=> 2a + 16d = 38

Solving eq 2 and eq 1 by elimination method..

=> 2a + 16d = 38

(-)2a -(+)3d =(-)0

------------------------

19d = 38

=> d = 2

Substituting d = 2 in eq 1

=> a+ 8(2) = 19

=> a+16=19

=> a= 3

Therefore the AP is 3,5,7,9......