the 19th term of an AP is equal to 3 times it's 6th term . If it's 9th term is 19 find AP
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a19=3a6
a+18d=3(a+5d)
a+18d=3a+15d
-2a+3d=0..1
a9=19
a+8d=19
(a+8d=19)2
2a+16d=38...2
Eliminating 1 and 2
-2a+3d=0
2a+16d=38
19d=38
d=2
a+8d=19
Putting value of d
a+16=19
a=3
A.P. =3,5,7,9...
Hope you like it
a+18d=3(a+5d)
a+18d=3a+15d
-2a+3d=0..1
a9=19
a+8d=19
(a+8d=19)2
2a+16d=38...2
Eliminating 1 and 2
-2a+3d=0
2a+16d=38
19d=38
d=2
a+8d=19
Putting value of d
a+16=19
a=3
A.P. =3,5,7,9...
Hope you like it
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