the 19th term of series -4,2,8.....
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The 19th term of series is 104
Step-by-step explanation:
GIVEN
a = t1 = -4 , t2 = 2 , t3 = 8
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To Find
19th term of a series
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We need to find the common difference first
We know that,
Common Difference (D) = t2 - t1
Common Difference (D) = 2 - (-4)
Common Difference (D) = 6
Common Difference (D) = 6
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We know that,
an = a + ( n - 1 ) × d
a19 = -4 + ( 19 - 1 ) × 6
a19 = -4 + 18 × 6
a19 = -4 + 108
a19 = 104
a19 = 104
The 19th term of series is 104
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