Question

the 1st,2nd and 4th term are 51,68and 108 find third term with explanation​

Answer 1

Given

Given First term =51

Given First term =51Second term =68

Given First term =51Second term =68fourth term =108

Given First term =51Second term =68fourth term =108Let the third term be x

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means⇒(51×108)=(68×x)

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means⇒(51×108)=(68×x)⇒(68×x)=(51×108)

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means⇒(51×108)=(68×x)⇒(68×x)=(51×108)⇒68x=5508

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means⇒(51×108)=(68×x)⇒(68×x)=(51×108)⇒68x=5508⇒x=

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means⇒(51×108)=(68×x)⇒(68×x)=(51×108)⇒68x=5508⇒x= 68

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means⇒(51×108)=(68×x)⇒(68×x)=(51×108)⇒68x=5508⇒x= 685508

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means⇒(51×108)=(68×x)⇒(68×x)=(51×108)⇒68x=5508⇒x= 685508

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means⇒(51×108)=(68×x)⇒(68×x)=(51×108)⇒68x=5508⇒x= 685508

Given First term =51Second term =68fourth term =108Let the third term be xSuch that the proportion is 51:68::x:108We know that Product of extremes = product of means⇒(51×108)=(68×x)⇒(68×x)=(51×108)⇒68x=5508⇒x= 685508 ∴x=81

Answer 2

Given

First term =51

Second term =68

fourth term =108

Let the third term be x

Such that the proportion is 51:68::x:108

We know that

Product of extremes = product of means

⇒(51×108)=(68×x)

⇒(68×x)=(51×108)

⇒68x=5508

⇒x=

68

5508

∴x=81

hope its helpful