The 1st and 2nd term of an AP are (a‐b)and (b‐a) respectievely then d=
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Answer:
D=2(b-a)
Step-by-step explanation:
1st term=a-b
2nd term=b-a
D=2ndterm-1st term
D=b-a-(a-b)
D=b-a-a+b
D=2b-2a
D=2(b-a)
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