the 1st line in the lyman series in the spectrum of hydrogen atom occurs at a wavelength of 1215 angstrom and the limit for Balmer series is 3645 angstrom. Calculate the wavelength corresponding to series limit of lyman series
Answers
Answered by
0
Explanation:
Wavelength of first line in Lyman series λ
L
=
4R
3
∴
3R
4
=1215.4A
o
We get R=
3×1215.4
4
Wavelength of first line in Balmer series λ
B
=
5R
36
⟹ λ
B
=
5×4
36×3×1215.4
=6563A
o
Similar questions