the 1st term of an A.P of Consecutive integer is p2+1.the sum of (2p+1) terms of this series can be expressed as..?
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your answer is here !
Step-by-step explanation:
The formula for finding the sum to the nth term of an AP is
In this question:
a = p² + 1
d = 1 (They are consecutive integers)
n = 2p + 1
Substitute these in the above formula
Sn = (2p+1)/2{2(p² + 1) + (2p+1 -1)(1)}
Sn = (2p+1)/2{2p² + 2 + 2p}
Sn = (2p+1)(p²+p+1)
Sn = 2p³ + 3p² + 1
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